The molar mass of the water insoluble product formed from the fusion of chromite ore \(FeCr_2\text{O}_4\) with \(Na_2\text{CO}_3\) in presence of \(O_2\) is ....... g mol\(^{-1}\):
To solve this problem, we need to identify the insoluble product formed in the reaction and then calculate its molar mass.
1. Identifying the Reaction:
Chromite ore ($FeCr_2O_4$) reacts with sodium carbonate ($Na_2CO_3$) and oxygen ($O_2$) to form sodium chromate ($Na_2CrO_4$), iron(III) oxide ($Fe_2O_3$), and carbon dioxide ($CO_2$).
The balanced chemical equation is:
$4FeCr_2O_4(s) + 8Na_2CO_3(s) + O_2(g) \rightarrow 8Na_2CrO_4(aq) + 2Fe_2O_3(s) + 8CO_2(g)$
2. Identifying the Insoluble Product:
From the reaction, sodium chromate is soluble, while iron(III) oxide ($Fe_2O_3$) is insoluble.
3. Calculating the Molar Mass of $Fe_2O_3$:
Given:
Molar mass of Fe = 56 g/mol
Molar mass of O = 16 g/mol
Molar mass of $Fe_2O_3$ = (2 × Molar mass of Fe) + (3 × Molar mass of O) = (2 × 56 g/mol) + (3 × 16 g/mol) = 112 g/mol + 48 g/mol = 160 g/mol
Final Answer:
The molar mass of the insoluble product $Fe_2O_3$ is 160 g/mol.
Chromite ore, with the formula FeCr₂O₄, contains iron (Fe) and chromium (Cr). When it’s heated (fused) with sodium carbonate (Na₂CO₃) and oxygen (O₂), a chemical reaction occurs. This is a common process to extract chromium from its ore.
The balanced chemical equation for the reaction is:
4FeCr₂O₄ + 8Na₂CO₃ + 7O₂ → 2Fe₂O₃ + 8NaCrO₂ + 8CO₂
Reactants: FeCr₂O₄ (chromite ore), Na₂CO₃ (sodium carbonate), O₂ (oxygen).
Products:
The question asks for the water-insoluble product. Let’s analyze the products:
Therefore, the water-insoluble product is Fe₂O₃.
The molar mass of a compound is the sum of the atomic masses of its atoms. Let’s calculate for Fe₂O₃:
Atomic masses:
Fe₂O₃ has 2 iron atoms and 3 oxygen atoms:
Total molar mass of Fe₂O₃ = 111.70 + 48.00 = 159.70 g/mol
The molar mass of the water-insoluble product (Fe₂O₃) is 159.70 g/mol.

Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).
