Cp = 20.785 JK-1 mol-1 and ΔU = nCvΔT
∴ nCv = \(\frac{5000}{200}\) = 25
and we know that
Cp – Cv = R
20.785\(-\frac{25}{n} \)= 8.314
n = \(\frac{25}{(20.785-8.314)}\)
= 2
List-I-Complex | List-II-CFSE | ||
A | [Cu(NH3)6]2+ | I | -0.6 |
B | [Ti(H2O)6]3+ | II | -2.0 |
C | [Fe(CN)6]3− | III | -1.2 |
D | [NiF6]4- | IV | -0.4 |
Specific heat of a solid or liquid is the amount of heat that raises the temperature of a unit mass of the solid through 1°C.
The Molar specific heat of a solid or liquid of a material is the heat that you provide to raise the temperature of one mole of solid or liquid through 1K or 1°C.
The volume of solid remains constant when heated through a small range of temperature. This is known as specific heat at a constant volume. It is denoted as CV.
The pressure of solid remains constant when heated through a small range of temperature. This is known as specific heat at constant pressure which can be denoted as CP.