The correct answer is (C) : 6
α + β = a – 3, αβ = 1 – 2a
⇒ α2 + β2 = (a – 3)2 – 2(1– 2a)
= a2 – 6a + 9 – 2 + 4a
= a2 – 2a + 7
= (a – 1)2 + 6
So,
α2 + β2 ≥ 6
If the roots of the quadratic equation \( ax^2 + bx + c = 0 \) are real and equal, then:
A polynomial that has two roots or is of degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b, and c are the real numbers.
Consider the following equation ax²+bx+c=0, where a≠0 and a, b, and c are real coefficients.
The solution of a quadratic equation can be found using the formula, x=((-b±√(b²-4ac))/2a)
Read More: Nature of Roots of Quadratic Equation