\(\dfrac{23}{7}\)
\(\dfrac{4}{7}\)
\(\dfrac{-4}{7}\)
\(\dfrac{16}{7}\)
\(\dfrac{17}{7}\)
Given: Mean deviation about the median data= \(3,5,9,3,8,10,7\)
arranging it in ascending order =\(3,3,5,7,8,9,10\)
Hence observation(\(n\))=\(7\)
median=\(\dfrac{n+1}{2}=\dfrac{7+1}{2}=4\)
Now, the mean deviation about the median= \(\dfrac{|3−7∣+|3−7|+|5−7|+|7−7|+|8−7|+∣9−7∣+∣10−7∣}{7}\)=\(\dfrac{16}{7}\)
First, we need to arrange the data in ascending order:
\[ 3, 3, 5, 7, 8, 9, 10 \]There are 7 observations, so the median is the middle value, which is 7.
Next, we calculate the absolute deviations from the median (7):
\[ |3 - 7| = 4, \quad |3 - 7| = 4, \quad |5 - 7| = 2, \quad |7 - 7| = 0, \quad |8 - 7| = 1, \quad |9 - 7| = 2, \quad |10 - 7| = 3 \]Now, sum the absolute deviations:
\[ 4 + 4 + 2 + 0 + 1 + 2 + 3 = 16 \]The mean deviation about the median is the average of these absolute deviations:
\[ \text{Mean Deviation} = \frac{\text{Sum of absolute deviations}}{\text{Number of observations}} = \frac{16}{7} \]Therefore, the mean deviation about the median for the given data is \( \frac{16}{7} \).
Find the mean deviation of the following data:
If $ X = A \times B $, $ A = \begin{bmatrix} 1 & 2 \\-1 & 1 \end{bmatrix} $, $ B = \begin{bmatrix} 3 & 6 \\5 & 7 \end{bmatrix} $, find $ x_1 + x_2 $.
According to layman’s words, the variance is a measure of how far a set of data are dispersed out from their mean or average value. It is denoted as ‘σ2’.
Read More: Difference Between Variance and Standard Deviation
The spread of statistical data is measured by the standard deviation. Distribution measures the deviation of data from its mean or average position. The degree of dispersion is computed by the method of estimating the deviation of data points. It is denoted by the symbol, ‘σ’.
1. Population Standard Deviation
2. Sample Standard Deviation