The mean deviation about the median for the data 3, 5, 9,3, 8, 10, 7 is
\(\frac 47\)
\(-\frac 47\)
\(\frac {16}{7}\)
\(-\frac {16}{7}\)
The given data,
\(3, 5, 9,3,8,10,7\)
Arrange the data in ascending order,
\(3,3,5,7,8,9,10\)
No. of observations \(N= 7\) (Odd)
Then, Median M= \(\frac {7+1}{2}= 4\)th term = \(7\)
Now mean deviation about median,
\(=\dfrac{∑|x_i−M|}{N}\)
\(=\frac {|3-7|+|3-7|+|5-7|+|7-7|+|8-7|+|9-7|+|10-7|}{7}\)
\(=\frac {4+4+2+0+1+2+3}{7}\)
\(=\frac {16}{7}\)
So, the correct option is (C): \(\frac {16}{7}\)
xi | 2 | 4 | 6 | 8 | 10 | 12 | 14 | 16 |
fi | 4 | 4 | α | 15 | 8 | β | 4 | 5 |
A statistical measure that is used to calculate the average deviation from the mean value of the given data set is called the mean deviation.
The mean deviation for the given data set is calculated as:
Mean Deviation = [Σ |X – µ|]/N
Where,
Grouping of data is very much possible in two ways: