Question:
The mass defect in a particular reaction is \( 0.4 \, \text{g} \). The amount of energy liberated is \( n \times 10^7 \, \text{kWh} \), where \( n = \) _____. (speed of light \( = 3 \times 10^8 \, \text{m/s} \))
The mass defect in a particular reaction is \( 0.4 \, \text{g} \). The amount of energy liberated is \( n \times 10^7 \, \text{kWh} \), where \( n = \) _____. (speed of light \( = 3 \times 10^8 \, \text{m/s} \))
Updated On: July 22, 2025
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Correct Answer: 1
Solution and Explanation
The energy liberated is given by:
\[ E = \Delta m c^2 \]
Substituting the values:
\[ E = 0.4 \times 10^{-3} \times (3 \times 10^8)^2 \]
\[ E = 3600 \times 10^7 \, \text{kWs} \]
Converting to kWh:
\[ E = \frac{3600 \times 10^7 \, \text{kWh}}{3600} = 1 \times 10^7 \, \text{kWh} \]
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