The reaction involves the interaction of a nucleophile (\( \text{HS-} \)) with an electrophilic site on the given substrate.
- \( \text{SH} \) is a better nucleophile than \( \text{OH} \) due to the softness of sulfur compared to oxygen.
- Soft nucleophiles prefer to attack soft electrophilic centers, following the principle of hard-soft acid-base (HSAB) theory.
The mechanism proceeds as follows:
1. The sulfur atom in \( \text{SH} \) attacks the electrophilic carbon of the \( \text{C=N} \) group.
2. This leads to the formation of a new bond between sulfur and carbon.
3. The \( \text{OH} \) group remains intact as sulfur is the more reactive nucleophile in this scenario.
The major product of the reaction is:
\[
\text{HO-CH(SH)-CN}.
\]
Thus, the correct product matches option (2).
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