>
Exams
>
Chemistry
>
Aldehydes, Ketones and Carboxylic Acids
>
the major product formed in the following reaction
Question:
The major product formed in the following reaction is
A.
B.
C.
D.
Choose the correct answer from the options given below:
JEE Main - 2023
JEE Main
Updated On:
Jan 13, 2025
C only
A only
D only
B only
Hide Solution
Verified By Collegedunia
The Correct Option is
D
Solution and Explanation
The correct option is (D): B only
Download Solution in PDF
Was this answer helpful?
0
0
Top Questions on Aldehydes, Ketones and Carboxylic Acids
Ethanal to But-2-enal
CBSE CLASS XII - 2025
Chemistry
Aldehydes, Ketones and Carboxylic Acids
View Solution
Give IUPAC name of \( CH_3 = CH - CH = CH - CHO \).
CBSE CLASS XII - 2025
Chemistry
Aldehydes, Ketones and Carboxylic Acids
View Solution
Explain the following reactions and write chemical equations involved:
(a) Wolff-Kishner reduction
(b) Etard reaction
(c) Cannizzaro reaction
CBSE CLASS XII - 2025
Chemistry
Aldehydes, Ketones and Carboxylic Acids
View Solution
Would you expect benzaldehyde to be more reactive or less reactive in nucleophilic addition reactions than propanal? Justify your answer.
CBSE CLASS XII - 2025
Chemistry
Aldehydes, Ketones and Carboxylic Acids
View Solution
The acid formed when propyl magnesium bromide is treated with CO$_2$ followed by acid hydrolysis is:
CBSE CLASS XII - 2025
Chemistry
Aldehydes, Ketones and Carboxylic Acids
View Solution
View More Questions
Questions Asked in JEE Main exam
If \( \alpha + i\beta \) and \( \gamma + i\delta \) are the roots of the equation \( x^2 - (3-2i)x - (2i-2) = 0 \), \( i = \sqrt{-1} \), then \( \alpha\gamma + \beta\delta \) is equal to:
JEE Main - 2025
Matrices and Determinants
View Solution
The product B formed in the following reaction sequence is:
\[ {C}_6{H}_5{CN} \xrightarrow{{HCl}} (A) \xrightarrow{{AgCN}} (B) \]
JEE Main - 2025
Organic Chemistry
View Solution
What are the units of viscosity, intensity of wave, and pressure gradient?
JEE Main - 2025
Units and measurement
View Solution
If the system of equations
\[ (\lambda - 1)x + (\lambda - 4)y + \lambda z = 5 \] \[ \lambda x + (\lambda - 1)y + (\lambda - 4)z = 7 \] \[ (\lambda + 1)x + (\lambda + 2)y - (\lambda + 2)z = 9 \]
has infinitely many solutions, then \( \lambda^2 + \lambda \) is equal to:
JEE Main - 2025
Matrices and Determinants
View Solution
Let \( P_n = \alpha^n + \beta^n \), \( P_{10} = 123 \), \( P_9 = 76 \), \( P_8 = 47 \), and \( P_1 = 1 \). The quadratic equation whose roots are \( \frac{1}{\alpha} \) and \( \frac{1}{\beta} \) is:
JEE Main - 2025
Sequences and Series
View Solution
View More Questions