\(\frac{hc}{E\lambda - hc}\)
\(\frac{hc\lambda}{E\lambda + hc}\)
\(\frac{h\lambda}{E\lambda + hc}\)
\(\frac{hc\lambda}{E\lambda - hc}\)
\(k = \frac{hc}{\lambda} - \Phi = E\)
and,
\(2k = \frac{hc}{\lambda^2} - \Phi = 2E\)
\(⇒\)\(\frac{hc}{\lambda} - E = \frac{hc}{\lambda^2} - 2E\)
\(⇒\) \(\frac{hc}{\lambda^2} = \frac{hc}{\lambda} + E\)
\(⇒\) \(\lambda^2 = \frac{hc\lambda}{hc + \lambda E}\)
So, the correct option is (B).
A bob of mass \(m\) is suspended at a point \(O\) by a light string of length \(l\) and left to perform vertical motion (circular) as shown in the figure. Initially, by applying horizontal velocity \(v_0\) at the point ‘A’, the string becomes slack when the bob reaches at the point ‘D’. The ratio of the kinetic energy of the bob at the points B and C is: 

Nature of compounds TeO₂ and TeH₂ is___________ and ______________respectively.
When light shines on a metal, electrons can be ejected from the surface of the metal in a phenomenon known as the photoelectric effect. This process is also often referred to as photoemission, and the electrons that are ejected from the metal are called photoelectrons.
According to Einstein’s explanation of the photoelectric effect :
The energy of photon = energy needed to remove an electron + kinetic energy of the emitted electron
i.e. hν = W + E
Where,