Step 1: Understanding hybridization in graphite.
In graphite, each carbon atom is bonded to three other carbon atoms in a plane, forming hexagonal rings. The bonding involves the use of \( sp^2 \) hybrid orbitals, with the remaining p-orbital involved in \( \pi \)-bonding, which accounts for the delocalized electrons in graphite.
Step 2: Explanation.
The \(sp^2\) hybridization allows for the formation of three sigma bonds and one pi bond, contributing to the structure of graphite.
Step 3: Conclusion.
Thus, the hybridization of carbon in graphite is \(sp^2\).