The question focuses on identifying the nature of the oxide formed by a transition metal 'M' that has the highest enthalpy of atomisation in its series, and where its aquated ion exists in green color. Let's break down the solution step-by-step:
Therefore, the correct answer is basic.
Let \( \alpha = \dfrac{-1 + i\sqrt{3}}{2} \) and \( \beta = \dfrac{-1 - i\sqrt{3}}{2} \), where \( i = \sqrt{-1} \). If
\[ (7 - 7\alpha + 9\beta)^{20} + (9 + 7\alpha - 7\beta)^{20} + (-7 + 9\alpha + 7\beta)^{20} + (14 + 7\alpha + 7\beta)^{20} = m^{10}, \] then the value of \( m \) is ___________.