Step 1: Atomic Configuration and Valence Electrons
Chromium (Cr):
Atomic number = 24. Its electron configuration is \([ \text{Ar} ] 3d^5 4s^1\), giving it 6 valence electrons
Cobalt (Co):
Atomic number = 27. Its electron configuration is \([ \text{Ar} ] 3d^7 4s^2\), giving it 9 valence electrons
Iron (Fe):
Atomic number = 26. Its electron configuration is \([ \text{Ar} ] 3d^6 4s^2\), giving it 8 valence electrons
Nickel (Ni):
Atomic number = 28. Its electron configuration is \([ \text{Ar} ] 3d^8 4s^2\), giving it 10 valence electrons
Step 2: Relation to Enthalpy of Atomisation
Enthalpy of atomisation generally decreases as the number of valence electrons increases, because more electrons lead to stronger metallic bonding and thus require more energy to break the bonds.
Therefore, the element with fewer valence electrons will have the lowest enthalpy of atomisation. Since Cr has 6 valence electrons, it will have the lowest enthalpy of atomisation compared to Co, Fe, and Ni.
Thus, the correct answer is 6 valence electrons.
Step 1:
The enthalpy of atomisation is the energy required to separate 1 mole of metal atoms from the metallic lattice into individual atoms in the gas phase.
Metals with higher valence electrons typically have stronger metallic bonding and hence, a higher enthalpy of atomisation. On the other hand, metals with fewer valence electrons tend to have a lower enthalpy of atomisation.
Now, let us consider the electronic configurations of the given metals:
Step 2:
Among these, Iron (Fe) has the lowest number of valence electrons (6). This typically corresponds to a lower enthalpy of atomisation compared to metals with more valence electrons (like Co, Ni, and Cr).
Final Answer:
\[ \boxed{6} \]


For the circuit shown above, the equivalent gate is:
Let \( f : \mathbb{R} \to \mathbb{R} \) be a twice differentiable function such that \[ (\sin x \cos y)(f(2x + 2y) - f(2x - 2y)) = (\cos x \sin y)(f(2x + 2y) + f(2x - 2y)), \] for all \( x, y \in \mathbb{R}. \)
If \( f'(0) = \frac{1}{2} \), then the value of \( 24f''\left( \frac{5\pi}{3} \right) \) is: