Question:

The graph drawn between \( \log \left( \frac{x}{m} \right) \) and \( \log (p) \) is shown below with intercept OA. What is the value of \( \frac{x}{m} \) at a pressure of 0.3 atm? (log 2 = 0.30, log 3 = 0.477)

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Use logarithmic relations to convert pressure values and find the corresponding ratio of \( \frac{x}{m} \).
Updated On: May 15, 2025
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The Correct Option is A

Solution and Explanation

The graph shows a relationship between the log of \( \frac{x}{m} \) and the log of pressure. By applying the equation for the graph at the given pressure, we can calculate \( \frac{x}{m} \). From the equation, we get: \[ \log \left( \frac{x}{m} \right) = 0.477 \times \log (0.3) \] Using the known logarithmic values for \( \log (0.3) = 0.477 \), we compute the value of \( \frac{x}{m} \). Thus, the value of \( \frac{x}{m} \) at the pressure of 0.3 atm is \( \boxed{0.6} \).
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