Step 1: Recall the formula for density of a gas
The density \( \rho \) of a gas at STP (Standard Temperature and Pressure) is given by:
\[
\rho = \frac{\text{Molar mass}}{\text{Molar volume at STP}}
\]
At STP, the molar volume of any ideal gas is approximately \( 22.4 \, \text{L/mol} \).
Step 2: Compare the molar masses of the gases
- Molar mass of \( \text{CO}_2 \) = \( 12 + 2 \times 16 = 44 \, \text{g/mol} \),
- Molar mass of \( \text{O}_2 \) = \( 2 \times 16 = 32 \, \text{g/mol} \),
- Molar mass of \( \text{N}_2 \) = \( 2 \times 14 = 28 \, \text{g/mol} \),
- Molar mass of \( \text{CH}_4 \) = \( 12 + 4 \times 1 = 16 \, \text{g/mol} \).
Step 3: Determine the gas with the highest density
Since the density of a gas is directly proportional to its molar mass at STP, \( \text{CO}_2 \) has the highest molar mass and hence the highest density at STP.
Answer: Therefore, \( \text{CO}_2 \) has the highest density at STP. So, the correct answer is option (1).