Question:

The function $f(x) = \tan x - 4x$ is strictly decreasing on

Updated On: Jun 24, 2024
  • $\left( - \frac{\pi}{3} , \frac{\pi}{3} \right)$
  • $\left( \frac{\pi}{3} , \frac{\pi}{2} \right)$
  • $\left( - \frac{\pi}{3} , \frac{\pi}{2} \right)$
  • $\left( \frac{\pi}{2} ,\pi \right)$
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The Correct Option is A

Solution and Explanation

The correct option is (A): \(\left(\frac{-\pi}{3}, \frac{\pi}{3}\right)\).
\(f(x)=\tan x-4 x \Rightarrow f'(x)=\sec ^{2} x-4\) 
When \(\frac{-\pi}{3} < x < \frac{\pi}{3}, 1 < \sec x < 2\) 
Therefore, \(1 < \sec ^{2} x < 4\)
\(\Rightarrow-3 < \left(\sec ^{2} x-4\right) < 0\) 
Thus, for \(\frac{-\pi}{3} < x < \frac{\pi}{3}, f'(x) < 0\) 
Hence, \(f\) is strictly decreasing on 
\(\left(\frac{-\pi}{3}, \frac{\pi}{3}\right)\)
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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions