Question:
The following diagram shows the kinetic energy of the ejected photoelectrons against the energy of incident radiation for two metal surfaces M1 and M2. If the energy of the incident radiation on M1 is equal to the work function of M2, the de Broglie wavelength of the ejected photoelectron is nm
[Given: Mass of electron = 9.11x10−31 kg; Planck’s constant = 6.62x10−34 J s; 1 eV=1.6x10−19 J.]
(round off to two decimal places)
The following diagram shows the kinetic energy of the ejected photoelectrons against the energy of incident radiation for two metal surfaces M1 and M2. If the energy of the incident radiation on M1 is equal to the work function of M2, the de Broglie wavelength of the ejected photoelectron is nm
[Given: Mass of electron = 9.11x10−31 kg; Planck’s constant = 6.62x10−34 J s; 1 eV=1.6x10−19 J.]
(round off to two decimal places)
[Given: Mass of electron = 9.11x10−31 kg; Planck’s constant = 6.62x10−34 J s; 1 eV=1.6x10−19 J.]
(round off to two decimal places)
Updated On: Oct 1, 2024
Hide Solution
Verified By Collegedunia
Correct Answer: 1.58 - 1.59
Solution and Explanation
The correct answer is: 1.58 to 1.59 (approx)
Was this answer helpful?
1
0
Top Questions on Atomic Structure
- The decreasing order of atomic radii (pm) of \( \text{Li}, \, \text{Be}, \, \text{B}, \, \text{C} \) is:
- NEET (UG) - 2024
- Chemistry
- Atomic Structure
- The number of radial node/s for 3p orbital is:
- JEE Main - 2024
- Chemistry
- Atomic Structure
- Frequency of the de-Broglie wave of the electron in Bohr's first orbit of the hydrogen atom is ______ \( \times 10^{13} \, \text{Hz} \) (nearest integer).
Given:\(R_H\) (Rydberg constant) = \(2.18 \times 10^{-18} \, \text{J}\)\(h\) \((\)Planck's constant)= \(6.6 \times 10^{-34}\)\(\text{J.s}\)- JEE Main - 2024
- Chemistry
- Atomic Structure
- Radius of a certain orbit of hydrogen atom is 8.48 Å. If energy of electron in this orbit is E/x, then x = ______.
(Given a0 = 0.529Å, E = energy of electron in ground state)- JEE Main - 2024
- Physics
- Atomic Structure
- In an atom, total number of electrons having quantum numbers n = 4, $|m_l|$ = 1 and $m_s$ = $-\frac{1}{2}$ is ________.
- JEE Main - 2024
- Chemistry
- Atomic Structure
View More Questions
Questions Asked in IIT JAM CY exam
- The bond length of CO is 113 pm and its dipole moment (𝜇⃗) is 0.1 D. The charge (in units of electronic charge) on carbon in the CO molecule including its sign is (rounded off to three decimal places)
[Given: charge of electron = 1.602×10−19 C; 1 D=3.336 × 10−30 Cm]- IIT JAM CY - 2024
- Chemical bonding and molecular structure
- A pair of isosteric compounds is
- IIT JAM CY - 2024
- Molecular structure and Chemical bonding
- A reaction of 10.50 g of 1,2-diphenylethane-1,2-dione with conc. NaOH followed by aqueous acidic work-up furnished 8.55 g of a carboxylic acid. The yield of the carboxylic acid in this reaction is _______ %.
(rounded off to the nearest integer)- IIT JAM CY - 2024
- Reaction Mechanisms & Synthesis
- If 1 M of a dye in water transmits 50% of incident light at 400 nm, then 2 M of the dye in water transmits _______ % of the incident light at 400 nm. (rounded off to the nearest integer)
[Given: Both experiments are performed in the same spectrophotometric cell.]- IIT JAM CY - 2024
- Spectroscopy
- A salt QCl of a certain metal Q is electrolyzed to its elements. 40 g of metal Q is formed at an electrode. The volume of Cl2 formed at the other electrode at 1 atm pressure and 298 K is _______ litres. (rounded off to one decimal place)
[Given: The gas constant 𝑅 = 0.082 L atm mol−1 K−1 , the molar mass of Q is 40 g mol−1 and Cl2 is assumed to be an ideal gas]- IIT JAM CY - 2024
- Electrochemistry
View More Questions