Question

The final product A, formed in the following reaction sequence is:

• A. \( \text{Ph} - \text{CH}_2 - \text{CH}_2 - \text{CH}_3 \)
• B.
• C.

  

• D. \( \text{Ph} - \text{CH}_2 - \text{CH}_2 - \text{CH}_2 - \text{OH} \)

Answer 1

The Correct Option is D

Step (i) involves hydroboration-oxidation of the double bond in \( \text{Ph-CH=CH}_2 \), resulting in the anti-Markovnikov addition of water to form \( \text{Ph-CH}_2\text{-CH}_2\text{-OH} \).

Step (ii) converts the alcohol \( (\text{Ph-CH}_2\text{-CH}_2\text{-OH}) \) to the corresponding alkyl halide \( (\text{Ph-CH}_2\text{-CH}_2\text{-Br}) \) using \( \text{HBr} \).

Step (iii) involves the formation of a Grignard reagent with \( \text{Mg} \), producing \( \text{Ph-CH}_2\text{-CH}_2\text{-MgBr} \).

Step (iv) reacts the Grignard reagent with formaldehyde (\( \text{HCHO} \)) followed by hydrolysis to yield the final primary alcohol, \( \text{Ph-CH}_2\text{-CH}_2\text{-CH}_2\text{-OH} \).

Thus, the final product is:

\(\text{Ph-CH}_2\text{-CH}_2\text{-CH}_2\text{-OH}.\)

The Correct answer is : \(\text{Ph-CH}_2\text{-CH}_2\text{-CH}_2\text{-OH}.\)