Question:
The expression for electric field intensity at a point outside uniformly charged thin plane sheet is (d is the distance of point from plane sheet)
The expression for electric field intensity at a point outside uniformly charged thin plane sheet is (d is the distance of point from plane sheet)
Updated On: Jan 23, 2024
- independent of $ d$
- directly proportional to $\sqrt{d}$
- directly proportional to $d$
- directly proportional to $\frac{1}{\sqrt{d}}$
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The Correct Option is A
Solution and Explanation
We know that,
the electric field intensity outside the sheet is given by
$E_{\text {outside }}=\frac{\sigma}{2 \varepsilon_{0}}$
Therefore, the electric field intensity is independent of $d$.
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Concepts Used:
Gauss Law
Gauss law states that the total amount of electric flux passing through any closed surface is directly proportional to the enclosed electric charge.
Gauss Law:
According to the Gauss law, the total flux linked with a closed surface is 1/ε0 times the charge enclosed by the closed surface.
For example, a point charge q is placed inside a cube of edge ‘a’. Now as per Gauss law, the flux through each face of the cube is q/6ε0.
Gauss Law Formula:
As per the Gauss theorem, the total charge enclosed in a closed surface is proportional to the total flux enclosed by the surface. Therefore, if ϕ is total flux and ϵ0 is electric constant, the total electric charge Q enclosed by the surface is;
Q = ϕ ϵ0
The Gauss law formula is expressed by;
ϕ = Q/ϵ0
Where,
Q = total charge within the given surface,
ε0 = the electric constant.