To determine the locus of the circumcentre, we consider the properties of the triangle and its relation to the parabola. The triangle’s sides along the y-axis and the line y = 3 form a right angle at the origin. The third side, tangent to the parabola, gives a specific geometric condition that must be analyzed to find the tangent line’s slope and intersection points. Using the derivative of the parabola y2 = 6x:
\(\frac{dy}{dx} = \frac{6}{2y} = \frac{3}{y}\)
Setting this equal to the slope of the tangent line and solving for y and x coordinates of the point of tangency, we can derive the general equation of the tangent line. Subsequent use of circumcentre formulae in a coordinate geometry setting yields the locus as a line equation.
\(y^2=6x\; \&\;y^2=4ax\)
\(⇒4a=6⇒a=23\)

\(y=mx+2m^3;(m\neq0)\)
\(h=\frac{6m−3}{4m^2},k=\frac{6m+3}{4m}\), Now eliminating m and we get
\(⇒3h=2(−2k^2+9k−9)\)
\(⇒4y^2−18y+3x+18=0\)
\(\text{The Correct Option is (C):}\) \(4 y^2+18 y+3 x+18=0\)
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).


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