Question:

The equation \(r \cos \theta = 2a \sin^2 \theta\) represents the curve:

Updated On: Jan 10, 2025
  • \(x^3 = y^2(2a + x)\)
  • \(x^2 = y^2(2a + x)\)
  • \(x^3 = y^2(2a - x)\)
  • \(x^3 = y^2(2a + x)\)
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The Correct Option is C

Solution and Explanation

The given polar equation is:

\[ r \cos \theta = 2a \sin^2 \theta. \]

Step 1: Convert to Cartesian coordinates.

We know the following polar-to-Cartesian conversions:

\[ x = r \cos \theta, \quad y = r \sin \theta, \quad r^2 = x^2 + y^2. \]

Substitute \(x = r \cos \theta\) into the given equation:

\[ x = 2a \sin^2 \theta. \]

Using \(\sin^2 \theta = \frac{y^2}{r^2}\), substitute:

\[ x = 2a \cdot \frac{y^2}{r^2}. \]

Substitute \(r^2 = x^2 + y^2\):

\[ x = 2a \cdot \frac{y^2}{x^2 + y^2}. \]

Step 2: Simplify the equation.

Multiply through by \(x^2 + y^2\):

\[ x(x^2 + y^2) = 2ay^2. \]

Expand:

\[ x^3 + xy^2 = 2ay^2. \]

Rearrange:

\[ x^3 = y^2(2a - x). \]

Conclusion: The equation of the curve is:

\[ \boxed{x^3 = y^2(2a - x)}. \]

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