$3.15 \times 10^{-3}$ J
Step 1: The energy stored in a soap bubble due to surface tension is given by:
U = 4 π R² × 2T
where T
is the surface tension, and the factor of 2 is included because a soap bubble has both an inner and outer surface.
Step 2: Given:
Diameter = 4 cm = 0.04 m,
R = 0.02 m
T = 0.07 N/m
Step 3: Substituting the values:
U = 4 π (0.02)² × 2 (0.07)
Step 4: Simplifying:
U = 4 × 3.1416 × 0.0004 × 0.14
U = 7 × 10⁻⁴ J
Step 5: Therefore, the correct answer is (C).
Consider a water tank shown in the figure. It has one wall at \(x = L\) and can be taken to be very wide in the z direction. When filled with a liquid of surface tension \(S\) and density \( \rho \), the liquid surface makes angle \( \theta_0 \) (\( \theta_0 < < 1 \)) with the x-axis at \(x = L\). If \(y(x)\) is the height of the surface then the equation for \(y(x)\) is: (take \(g\) as the acceleration due to gravity)