The correct answer is (C) : \(2\sqrt2\)
AB = x – 2y + 1 = 0
AC = 2x – y - 1 = 0
So A(1, 1)

Altitude from B is BH \(= x + 2y – 7 = 0 ⇒ B (3, 2) \)
Altitude from C is CH \(= 2x + y – 7 = 0 ⇒ C (2, 3) \)
Centroid of ΔABC = E(2, 2) OE = \(2\sqrt2\)
In the given figure, the blocks $A$, $B$ and $C$ weigh $4\,\text{kg}$, $6\,\text{kg}$ and $8\,\text{kg}$ respectively. The coefficient of sliding friction between any two surfaces is $0.5$. The force $\vec{F}$ required to slide the block $C$ with constant speed is ___ N.
(Given: $g = 10\,\text{m s}^{-2}$) 
Method used for separation of mixture of products (B and C) obtained in the following reaction is: 