Question:
The digit at the unit place of P would be: Given, P=(6+1) (62+1) (63+1) ......... (6100+1)
The digit at the unit place of P would be: Given, P=(6+1) (62+1) (63+1) ......... (6100+1)
Updated On: Aug 31, 2024
- 7
- 9
- 1
- 3
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The Correct Option is C
Solution and Explanation
Unit digit of 6x=6, x is a natural no.
⇒ In P, the number of terms is 100 and each term has a unit digit ‘7’.
⇒ Unit digit of P = Unit digit of (\(7^{25\times4}\))=1
So the correct option is (C): 1.
⇒ In P, the number of terms is 100 and each term has a unit digit ‘7’.
⇒ Unit digit of P = Unit digit of (\(7^{25\times4}\))=1
So the correct option is (C): 1.
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