Question

The descending order of acidity for the following carboxylic acid is-
A. CH₃COOH
B. F₃C-COOH
C. CICH₂-COOH
D. FCH₂-COOH
E. BrCH₂-COOH
Choose the correct answer from the options given below:

• A. E>D>B>A>C
• B. B>C>D>E>A
• C. D>B>A>E>C
• D. B>D>C>E>A

Hint:

The more electronegative and closer the electron-withdrawing group is to the carboxyl group, the stronger the acid becomes.

Answer 1

The Correct Option is D

• Acidic Strength is inversely proportional to the \(+I\) effect and directly proportional to the \(-I\) effect.
• The \(-I\) effect order of halogens is: F > Cl > Br. 

Compound Analysis:

1. (A) CH₃−COOH : The methyl group exhibits a \(+I\) effect, which decreases acidic strength.
2. (B) F−C(F)−F−COOH: Contains three fluorine atoms with a strong \(-I\) effect, significantly increasing acidic strength.
3. (C) Cl−CH₂−COOH : The chlorine atom exhibits a \(-I\) effect, increasing acidic strength but less than fluorine.
4. (D) F−CH₂−COOH : Fluorine exhibits a stronger \(-I\) effect compared to chlorine, making this compound more acidic than (C).
5. (E) Br−CH₂−COOH : Bromine has the weakest \(-I\) effect among the halogens, so its acidic strength is less than (C) and (D).

Acidic Strength Order:

(B) > (D) > (C) > (E) > (A)