The correct order of hydration enthalpies is
(A) K+
(B) Rb2+
(C) Mg2+
(D) Cs+
(E) Ca2+
Choose the correct answer from the options given below:
For hydration enthalpy trends:
• Smaller ions with higher charges have greater hydration enthalpies.
• Compare ionic radii and charges to establish trends within groups and periods.
Hydration enthalpy depends on the charge density of ions, which is determined by the charge on the ion and its ionic radius.
Smaller ions with higher charges have higher hydration enthalpies due to stronger electrostatic interactions with water molecules.
For alkali metal ions:
\[\text{K}^+ > \text{Rb}^+ > \text{Cs}^+ \quad \text{(A > B > D)}.\]
This is because \(\text{K}^+\) is smaller than \(\text{Rb}^+\) and \(\text{Cs}^+\).
For alkaline earth metal ions:
\[\text{Mg}^{2+} > \text{Ca}^{2+} \quad \text{(C > E)}.\]
\(\text{Mg}^{2+}\) has a smaller radius and higher charge density than \(\text{Ca}^{2+}\).
Final Order:
\[\text{Mg}^{2+} > \text{Ca}^{2+} > \text{K}^+ > \text{Rb}^+ > \text{Cs}^+ \quad \text{(C > E > A > B > D)}.\]
Final Answer: \((4)\) \(\mathbf{C > E > A > B > D}\).
Two soap bubbles of radius 2 cm and 4 cm, respectively, are in contact with each other. The radius of curvature of the common surface, in cm, is _______________.
One mole of an ideal gas expands isothermally and reversibly from $10 \mathrm{dm}^{3}$ to $20 \mathrm{dm}^{3}$ at $300 \mathrm{~K} . \Delta \mathrm{U}$, q and work done in the process respectively are : Given : $\mathrm{R}=8.3 \mathrm{JK}^{-1}$ and $\mathrm{mol}^{-1}$ In $10=2.3$ $\log 2=0.30$ $\log 3=0.48$