To determine which compound is white in color, we need to examine the properties of each option. Let's evaluate them one by one:
From the above analysis, we can conclude that among the listed options, lead sulphate is distinctly known for its white coloration.
Therefore, the correct answer is lead sulphate.
Lead sulphate is white in color.
Ammonium sulphide is soluble.
Lead iodide is bright yellow.
Ammonium arsenomolybdate is yellow.
In the following \(p\text{–}V\) diagram, the equation of state along the curved path is given by \[ (V-2)^2 = 4ap, \] where \(a\) is a constant. The total work done in the closed path is: 
Let \( ABC \) be a triangle. Consider four points \( p_1, p_2, p_3, p_4 \) on the side \( AB \), five points \( p_5, p_6, p_7, p_8, p_9 \) on the side \( BC \), and four points \( p_{10}, p_{11}, p_{12}, p_{13} \) on the side \( AC \). None of these points is a vertex of the triangle \( ABC \). Then the total number of pentagons that can be formed by taking all the vertices from the points \( p_1, p_2, \ldots, p_{13} \) is ___________.