Question:

The circuit shown in the figure contains two diodes each with a forward resistance of 50 \(\Omega\) and with infinite backward resistance. If the battery voltage is 6 V, the current through the 100 \(\Omega\) resistance (in ampere) is
 
Circuit

Updated On: Aug 31, 2023
  • zero
  • 0.02
  • 0.03
  • 0.036
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The Correct Option is B

Solution and Explanation

The correct answer is B:0.02
In the circuit, diode \(D_1\) in forward biased, while \(D_2\) is reverse 
biased. Therefore, current \(i\) (through \(D_1\) and 100 \(\Omega\) 
resistance) will be 
\(i = \frac {6}{50 + 100 + 150} = 0.02A\) 
Here 50 \(\Omega\) is the resistance of \(D_1\) in forward biasing.
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Concepts Used:

P-n Junction

A P-N junction is an interface or a boundary between two semiconductor material types, namely the p-type and the n-type, inside a semiconductor.

Biasing conditions for the p-n Junction Diode:

in p-n junction diode two operating regions are there:

  • P-type
  • N-type

There are three biasing conditions for p-n junction diode are as follows:

  • Zero bias: When there is no external voltage applied to the p-n junction diode.
  • Forward bias: P-type is connected to positive terminal of the voltage potential while n-type is connected to the negative terminal.
  • Reverse bias: P-type is connected to negative terminal of the voltage potential while n-type is connected to the positive terminal.