Question:

The battery of a mobile phone is rated as 4.2 V, 5800 mAh. How much energy is stored in it when fully charged?

Show Hint

To calculate energy stored in a battery, use the formula \( E = Vq \), where \( V \) is the voltage and \( q \) is the charge in coulombs.
Updated On: Apr 27, 2025
  • 43.8 kJ
  • 48.7 kJ
  • 87.7 kJ
  • 24.4 kJ
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

Given the voltage \( V = 4.2 \) volts and the battery capacity \( 5800 \) mAh, we can calculate the energy stored in the battery using the formula: \[ \text{Energy supplied by battery} = Vq \] where \( q \) is the charge in coulombs. Converting \( 5800 \) mAh to coulombs: \[ q = 5800 \times 3600 \times 10^{-3} \, \text{C} = 5800 \times 3.6 \, \text{C} = 20880 \, \text{C} \] Thus, the energy supplied by the battery is: \[ \text{Energy} = 4.2 \times 5800 \times 3600 \times 10^{-3} = 87.696 \, \text{kJ} \] Therefore, the energy stored in the battery when fully charged is approximately \( 87.7 \, \text{kJ} \).
Was this answer helpful?
0
0

Top Questions on Electrostatics

View More Questions

Questions Asked in JEE Main exam

View More Questions