NH3>PH3>AsH3>SbH3
SbH3>AsH3>PH3>NH
NH3>AsH3>PH3>SbH3
NH3>SbH3>PH3>AsH3
SbH3>PH3>AsH3>NH3
Group 15 hydrides basicity trend:
Thus, the correct option is (A): NH3 > PH3 > AsH3 > SbH3.
1. Understanding the basic character of hydrides:
The basic character of a compound depends on its ability to donate a lone pair of electrons. For the hydrides of group 15 elements (NH3, PH3, AsH3, SbH3), the basicity decreases as the size of the central atom increases. This is because:
2. Analyze the hydrides of group 15 elements:
3. Arrange the hydrides in order of decreasing basicity:
4. Final answer:
The correct option is (A) NH3 > PH3 > AsH3 > SbH3.
Given below are two statements. 
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
Group 15 elements are also known as nitrogen group elements or nitrogen family.
It consists of:
They are present on the right side of the periodic table. All the elements are arranged based on their atomic weight. The elements with similar properties reside in a column called the group.
All Group 15 elements have the electron configuration ns2np3 in their outer shell, where n is the principal quantum number.
