The tetrathionate ion has the formula \({S}_4{O}_6^{2-}\). We can calculate the average oxidation state of sulfur by assuming that the oxygen is in the -2 oxidation state:
\[
4 \times {Oxidation state of S} + 6 \times (-2) = -2
\]
\[
4 \times {Oxidation state of S} - 12 = -2 \implies 4 \times {Oxidation state of S} = 10 \implies {Oxidation state of S} = +2.5
\]
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