Step 1: The lanthanides are the series of elements from \( {Ce} \) to \( {Lu} \) in the periodic table, and they involve filling the 4f orbitals. In the +3 oxidation state, these elements generally lose their 5s and 4d electrons, but the 4f electrons remain.
Step 2: In the case of gadolinium (\( {Gd} \)), the electronic configuration in the ground state is:
\[
{Gd (Z = 64):} \, [{Xe}] \, 4f^7 5s^2 5d^1.
\]
When it loses three electrons to form the +3 state, the electron configuration becomes:
\[
{Gd}^{3+}: [{Xe}] \, 4f^7.
\]
Thus, the 4f orbitals in gadolinium’s +3 state are half-filled (\( 4f^7 \)), which is a stable configuration due to the special stability of half-filled subshells.
Step 3: This half-filled configuration is a notable characteristic of gadolinium in its +3 oxidation state.
Thus, the correct answer is option (B).