Area =1∫2(x2−1)dx+2∫8(x8−1)dx
=(3x3)12+8(ℓnx)28−(x)18
=37+8(2ℓn2)−7
=16ln2−314
So, the correct option is (A): 16loge 2−314
If 5f(x) + 4f (\(\frac{1}{x}\)) = \(\frac{1}{x}\)+ 3, then \(18\int_{1}^{2}\) f(x)dx is:
There are distinct applications of integrals, out of which some are as follows:
In Maths
Integrals are used to find:
In Physics
Integrals are used to find: