Question:

The area of the region given by $\left\{(x, y): x y \leq 8,1 \leq y \leq x^2\right\}$ is :

Updated On: Sep 24, 2024
  • $16 \log _e 2-\frac{14}{3}$
  • $8 \log _e 2-\frac{13}{3}$
  • $8 \log _e 2+\frac{7}{6}$
  • $16 \log _e 2+\frac{7}{3}$
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is A

Solution and Explanation

Area =1∫2​(x2−1)dx+2∫8​(x8​−1)dx 
=(3x3​)12​+8(ℓnx)28​−(x)18​ 
=37​+8(2ℓn2)−7 
=16ln2−314​

So, the correct option is (A): 16loge​ 2−314​

Was this answer helpful?
0
0

Questions Asked in JEE Main exam

View More Questions

Concepts Used:

Applications of Integrals

There are distinct applications of integrals, out of which some are as follows:

In Maths

Integrals are used to find:

  • The center of mass (centroid) of an area having curved sides
  • The area between two curves and the area under a curve
  • The curve's average value

In Physics

Integrals are used to find:

  • Centre of gravity
  • Mass and momentum of inertia of vehicles, satellites, and a tower
  • The center of mass
  • The velocity and the trajectory of a satellite at the time of placing it in orbit
  • Thrust