In the brown ring test for nitrates, the compound formed is:
\([\text{Fe(H}_2\text{O)}_5(\text{NO})]^{2+}.\)
The oxidation number of Fe in this complex is:
\(+1\)
The Correct Answer is: +1
List - I(Test/reagent) | List - II(Radical identified) |
---|---|
(A) Lake Test | (I) NO3− |
(B) Nessler’s Reagent | (II) Fe3+ |
(C) Potassium sulphocyanide | (III) Al3+ |
(D) Brown Ring Test | (IV) NH4+ |
List - ISolid salt treated with dil. H2SO4 | List - IIAnion detected |
---|---|
(A) effervescence of colourless gas | (I) NO2− |
(B) gas with smell of rotten egg | (II) CO32− |
(C) gas with pungent smell | (III) S2− |
(D) brown fumes | (IV) SO23− |