Question:

Ten capacitors each of 2 µF capacity were arranged in two rows such that first row contains 6 capacitors in series where as the rest were in second row. The equivalent capacitance of the network is:

Updated On: Sep 12, 2024
  • \(\frac{5}{6}μF\)
  • 20μF
  • \(\frac{24}{5}μF\)
  • \(\frac{6}{5}μF\)
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The Correct Option is A

Solution and Explanation

The correct option is (A):
\(\frac{5}{6}μF\)
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