Question:

\( \tan^{-1} \sqrt{3} - \sec^{-1}(-2) \) is equal to:

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For inverse trigonometric functions, remember the values of common angles like \( \frac{\pi}{3}, \frac{\pi}{6}, \) and \( \frac{\pi}{4} \) for sine, cosine, and tangent.
  • \( \pi \)
  • \( \frac{\pi}{3} \)
  • \( \frac{\pi}{3} \)
  • \( \frac{2\pi}{3} \)
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The Correct Option is C

Solution and Explanation

Step 1: Using inverse trigonometric identities.
We know that \( \tan^{-1} \sqrt{3} = \frac{\pi}{3} \) and \( \sec^{-1}(-2) = \frac{2\pi}{3} \), so: \[ \tan^{-1} \sqrt{3} - \sec^{-1}(-2) = \frac{\pi}{3} - \frac{2\pi}{3} = -\frac{\pi}{3} \]

Step 2: Conclusion.
Thus, the correct value is \( \frac{\pi}{3} \), which corresponds to option (3).

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