It can be observed that the incomes that Subba Rao obtained in various years are in A.P. as every year, his salary is increased by Rs. \(200\).
Therefore, the salaries of each year after 1995 are:
\(5000, 5200, 5400, ……\)
Here,
\(a = 5000\) and \(d = 200\)
Let after \(n^{th}\) year, his salary be Rs. \(7000\).
Therefore,
\(a_n = a + (n − 1) d\)
\(7000 = 5000 + (n − 1) 200\)
\(200(n − 1) = 2000\)
\((n − 1) = 10\)
\(n = 11\)
Therefore, in \(11^{th}\) year, his salary will be Rs. \(7000\).
The common difference of the A.P.: $3,\,3+\sqrt{2},\,3+2\sqrt{2},\,3+3\sqrt{2},\,\ldots$ will be:
Let $a_1, a_2, a_3, \ldots$ be an AP If $a_7=3$, the product $a_1 a_4$ is minimum and the sum of its first $n$ terms is zero, then $n !-4 a_{n(n+2)}$ is equal to :
In the adjoining figure, \( AP = 1 \, \text{cm}, \ BP = 2 \, \text{cm}, \ AQ = 1.5 \, \text{cm}, \ AC = 4.5 \, \text{cm} \) Prove that \( \triangle APQ \sim \triangle ABC \).
Hence, find the length of \( PQ \), if \( BC = 3.6 \, \text{cm} \).
In the adjoining figure, $\triangle CAB$ is a right triangle, right angled at A and $AD \perp BC$. Prove that $\triangle ADB \sim \triangle CDA$. Further, if $BC = 10$ cm and $CD = 2$ cm, find the length of AD.