Question:

What is the sum of the infinite series \( S = \sum_{n=0}^{\infty} \frac{1}{3^n} \)?

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For an infinite geometric series with \( |r|<1 \), the sum is given by \( S = \frac{a}{1 - r} \).
Updated On: Jan 22, 2025
  • \( \frac{3}{2} \)
  • \( \frac{1}{2} \)
  • 2
  • 3
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The Correct Option is B

Solution and Explanation

This is a geometric series with the first term \( a = 1 \) and the common ratio \( r = \frac{1}{3} \). 

The sum of an infinite geometric series is given by the formula: \[ S = \frac{a}{1 - r}. \] 

Substituting \( a = 1 \) and \( r = \frac{1}{3} \): \[ S = \frac{1}{1 - \frac{1}{3}} = \frac{1}{\frac{2}{3}} = \frac{3}{2}. \] 

Thus, the sum of the series is \( \frac{3}{2} \).

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