First, let's denote:
The probability that Sonali does not solve the problem is:
P(S') = 1 - P(S) = 1 - 0.7 = 0.3
The probability that Nirali does not solve the problem is:
P(N') = 1 - P(N) = 1 - 0.6 = 0.4
The probability that neither Sonali nor Nirali solves the problem is:
P(S' ∩ N') = P(S') × P(N') = 0.3 × 0.4 = 0.12
The probability that at least one of them solves the problem is the complement of both not solving it:
P(S ∪ N) = 1 - P(S' ∩ N') = 1 - 0.12 = 0.88
The probability that at least one of them will solve the problem is 0.88.
Four students of class XII are given a problem to solve independently. Their respective chances of solving the problem are: \[ \frac{1}{2},\quad \frac{1}{3},\quad \frac{2}{3},\quad \frac{1}{5} \] Find the probability that at most one of them will solve the problem.
Two persons are competing for a position on the Managing Committee of an organisation. The probabilities that the first and the second person will be appointed are 0.5 and 0.6, respectively. Also, if the first person gets appointed, then the probability of introducing a waste treatment plant is 0.7, and the corresponding probability is 0.4 if the second person gets appointed.
Based on the above information, answer the following