The possible prime numbers that can be the sum of two dice are 3, 5, 7, and 11.
For each of these sums:
- 3: (1,2)
- 5: (1,4), (2,3)
- 7: (1,6), (2,5), (3,4)
- 11: (5,6)
Out of these, only the pairs where the number on the red die is greater than the blue die are considered. The favorable pairs are:
- (2,1), (3,2), (6,1), (5,2), (6,5)
Thus, the probability is:
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)