Let the total distance be \( D \). The man covers 1/3 of the total distance at each of the speeds. So, the time taken for each part of the journey is:
\[
t_1 = \frac{D/3}{10}, \quad t_2 = \frac{D/3}{20}, \quad t_3 = \frac{D/3}{60}
\]
The total time taken is:
\[
T = \frac{D}{3} \left( \frac{1}{10} + \frac{1}{20} + \frac{1}{60} \right) = \frac{D}{3} \times \frac{1}{5} = \frac{D}{15}
\]
The average speed is given by:
\[
\text{Average speed} = \frac{\text{Total distance}}{\text{Total time}} = \frac{D}{D/15} = 15 \text{ km/hr}
\]