Step 1: Separate the variables:
\[
\frac{dy}{y^2} = -4x \, dx
\]
Step 2: Integrate both sides:
\[
\int \frac{1}{y^2} \, dy = \int -4x \, dx
\]
The integral of \( \frac{1}{y^2} \) is \( -\frac{1}{y} \), and the integral of \( -4x \) is \( -2x^2 \).
Step 3: After integration, we get:
\[
-\frac{1}{y} = -2x^2 + C
\]
Step 4: Solve for \( y \):
\[
y = \frac{1}{x^2 + C}
\]