Question

Solve and check result: \(4z + 3 = 6 + 2z\)

Answer 1

\(4z + 3 = 6 + 2z\)
On transposing \(2z\) to L.H.S and \(3\) to R.H.S, we obtain
\(4z - 2z = 6 - 3\)
\(2z = 3\)
Dividing both sides by \(2\), we obtain 
\(z\) = \(\frac{3}{2}\)
\(\Rightarrow\) L.H.S = \(4z + 3\) 
= \(4 × (\frac{3}{2}) + 3\) 
=\(6 + 3\) = \(9\)
\(\Rightarrow\) R.H.S = \(6 + 2z\) 
= \(6 + 2 × (\frac{3}{2})\) 
= \(6 + 3 = 9\)
L.H.S. = R.H.S.

Hence, the result obtained above is correct.