\(2x - 1 = 14 - x\)
Transposing \(x\) to L.H.S and \(1\) to R.H.S, we obtain
\(2x + x = 14 + 1\)
\(3x = 15\)
Dividing both sides by \(3\), we obtain
\(x = 5\)
\(\Rightarrow\) L.H.S = \(2x - 1\)
= \(2 \times (5) - 1\)
= \(10 - 1 = 9\)
\(\Rightarrow\) R.H.S = \(14 - x\)
= \(14 - 5 = 9\)
L.H.S. = R.H.S.
Hence, the result obtained above is correct.