Question

The floor of a building consists of 3000 tiles which are rhombus shaped and each of its diagonals are 45 cm and 30 cm in length. Find the total cost of polishing the floor, if the cost per m² is Rs 4.

Answer 1

Length of one diagonal, d₁ = 45 cm and d₂= 30 cm
∵ Area of one tile = (\(\frac{1}{2}\))d₁d₂
= (\(\frac{1}{2}\))\(×45×30 = 675\)

Area of one tile is 675 cm²
Area of 3000 tiles is
\(= 675×3000 \)
\(= 2025000\) cm²
\(= \frac{2025000}{10000}\)
\(= 202.50\) m² [∵ 1m² = 10000 cm²]
∵ Cost of polishing the floor per sq. meter = 4

Cost of polishing the floor per 202.50 sq. meter \(= 4×202.50 = 810\)

Hence the total cost of polishing the floor is Rs. 810.