
Given that,
\(a = 5\), \(d = 1.75\) and \(a_n = 20.75\).
\(n = ?\)
\(a_n = a + (n − 1) d\)
\(20.75 = 5 + (n-1)1.75\)
\(15.75 = (n-1)1.75\)
\(n-1 = \frac {15.75}{1.75}\)
\(n-1 = \frac {1575}{175}\)
\(n-1 = \frac {63}{7}\)
\(n − 1 = 9\)
\(n = 10\)
Hence, n is 10.
The common difference of the A.P.: $3,\,3+\sqrt{2},\,3+2\sqrt{2},\,3+3\sqrt{2},\,\ldots$ will be:
 
Let $a_1, a_2, a_3, \ldots$ be an AP If $a_7=3$, the product $a_1 a_4$ is minimum and the sum of its first $n$ terms is zero, then $n !-4 a_{n(n+2)}$ is equal to :
The following data shows the number of family members living in different bungalows of a locality: 
 
| Number of Members | 0−2 | 2−4 | 4−6 | 6−8 | 8−10 | Total | 
|---|---|---|---|---|---|---|
| Number of Bungalows | 10 | p | 60 | q | 5 | 120 | 
If the median number of members is found to be 5, find the values of p and q.