Question

Products for the below reaction are:

• A.
• B.
• C.

Answer 1

The Correct Option is A

To determine the products of the given reaction, we need to consider the mechanism of the reaction between an ether and hydrogen iodide (HI). This reaction involves the cleavage of the C-O bond in the ether. 

1. The ether in the reaction is a cyclic structure with an isopropyl group attached to an oxygen atom.
2. When HI is added to this ether, the iodine (I^-) ion can attack the more sterically hindered carbon of the ether, leading to the formation of an alcohol and an alkyl iodide.
3. In this reaction, the more hindered side is the tertiary butyl group. The iodine ion will attack here, leading to the cleavage of the C-O bond.
4. This will produce isopropanol as the alcohol and tertiary butyl iodide as the alkyl iodide.

Therefore, the products of the reaction are isopropanol and tertiary butyl iodide.

Thus, the correct answer is the image showing isopropanol and tertiary butyl iodide.

Answer 2

The given reaction involves the cleavage of the ether bond using \( \text{HI} \). The major products are formed through the nucleophilic substitution of \( \text{HI} \) on the ether linkage. The reaction mechanism proceeds as follows:

Protonation of the ether oxygen atom by \( \text{HI} \), resulting in the formation of an oxonium ion intermediate.
Cleavage of the \( \text{C–O} \) bond forms cyclohexanol and a tertiary carbocation (\((\text{CH}_3)_3\text{C}^+\)).
The tertiary carbocation rapidly reacts with \( \text{I}^- \) to form \((\text{CH}_3)_3\text{C–I}\) as the final product.
The correct option is (A) :