Question

When the conversion of a liquid phase reaction of first order occurring in a CSTR is 60%, and the molar feed rate is 10 mol/min, and the volume of the reactor is 0.50 litre, then the reaction rate in mol/lit/min will be:

• A. 12
• B. 18
• C. 20
• D. 6

Hint:

For CSTRs, use the formula $-r_A = \frac{F_{A0}X}{V}$ directly when feed rate, conversion, and volume are known.

Answer 1

The Correct Option is A

We are given:
- Conversion $X = 60% = 0.6$
- Molar feed rate $F_A = 10 \ \text{mol/min}$
- Reactor volume $V = 0.5 \ \text{litres}$
For a Continuous Stirred Tank Reactor (CSTR), the reaction rate $-r_A$ is calculated using the formula:
\[ -r_A = \frac{F_{A0}X}{V} \]
Substitute the known values:
\[ -r_A = \frac{10 \times 0.6}{0.5} = \frac{6}{0.5} = 12 \ \text{mol/lit/min} \]
Therefore, the rate of reaction in the CSTR is $12 \ \text{mol/lit/min}$.