We are considering an ideal gas that undergoes two distinct cyclic processes, denoted as I and II. The stages of the first cycle, Cycle I, are represented as follows:
Cycle I: Stages a, b, c, and d
1. **Isobaric (Stage a and c)**: In this stage, the pressure of the gas remains constant while the volume changes. During an isobaric process, the work done on or by the gas is given by \( W = P \Delta V \), where \( P \) is the pressure, and \( \Delta V \) is the change in volume.
2. **Isothermal (Stage b)**: In this stage, the temperature of the gas remains constant. For an ideal gas undergoing an isothermal process, the internal energy change is zero, and the work done is given by the equation \( W = nRT \ln \left( \frac{V_f}{V_i} \right) \), where \( V_f \) and \( V_i \) are the final and initial volumes, respectively.
3. **Isochoric (Stage d)**: In this stage, the volume of the gas remains constant. Since there is no change in volume, no work is done during the isochoric process. However, heat may be transferred, resulting in a change in the internal energy of the gas.
As described, the stages of cycle I include isobaric, isothermal, isobaric, and isochoric transformations. The answer to the problem, based on this analysis, is:
The answer is 2.
\[ W_I = W_a + W_b + W_c + W_d \]\[ = 4P_0 \left(2V_0 - V_0\right) + nRT \ln\left(\frac{4V_0}{2V_0}\right) + 2P_0 \left(V_0 - 4V_0\right) + 0 \] \[ = 4P_0 V_0 + nRT \ln\left(\frac{8P_0 V_0}{nR}\right) \ln 2 - 6P_0 V_0 \] \[ = 8P_0 V_0 \ln 2 - 2P_0 V_0 \] \[ W_{II} = W_a' + W_b' + W_c' + W_d' \] \[ = nRT \ln\left(\frac{2V_0}{V_0}\right) + 0 + P_0 \left(V_0 - 2V_0\right) + 0 \] \[ = nRT \ln\left(\frac{4P_0 V_0}{nR}\right) \ln 2 - P_0 V_0 \] \[ = 4P_0 V_0 \ln 2 - P_0 V_0 \] \[ \frac{W_I}{W_{II}} = \frac{8P_0 V_0 \ln 2 - 2P_0 V_0}{4P_0 V_0 \ln 2 - P_0 V_0} = 2 \] The ratio \( \frac{W_I}{W_{II}} \) is 2,Therefore the Correct Answer is 2.
Two identical concave mirrors each of focal length $ f $ are facing each other as shown. A glass slab of thickness $ t $ and refractive index $ n_0 $ is placed equidistant from both mirrors on the principal axis. A monochromatic point source $ S $ is placed at the center of the slab. For the image to be formed on $ S $ itself, which of the following distances between the two mirrors is/are correct:
Thermodynamics in physics is a branch that deals with heat, work and temperature, and their relation to energy, radiation and physical properties of matter.
A thermodynamic system is a specific portion of matter with a definite boundary on which our attention is focused. The system boundary may be real or imaginary, fixed or deformable.
There are three types of systems:
A system undergoes a thermodynamic process when there is some energetic change within the system that is associated with changes in pressure, volume and internal energy.
There are four types of thermodynamic process that have their unique properties, and they are:
The Zeroth law of thermodynamics states that if two bodies are individually in equilibrium with a separate third body, then the first two bodies are also in thermal equilibrium with each other.
The First law of thermodynamics is a version of the law of conservation of energy, adapted for thermodynamic processes, distinguishing three kinds of transfer of energy, as heat, as thermodynamic work, and as energy associated with matter transfer, and relating them to a function of a body's state, called internal energy.
The Second law of thermodynamics is a physical law of thermodynamics about heat and loss in its conversion.
Third law of thermodynamics states, regarding the properties of closed systems in thermodynamic equilibrium: The entropy of a system approaches a constant value when its temperature approaches absolute zero.