From the given information, the temperature scale \( X \) has the following relationships:
The boiling point of water is 65° X and the freezing point is 15° X, so the scale has a linear relation between these two points. Let's use the formula for converting between temperature scales:
\[
F = X \times \frac{9}{5} + 32
\]
Now, to convert 95° X to Fahrenheit:
\[
F = 95 \times \frac{9}{5} + 32 = 171 + 32 = 148° F
\]
Thus, the equivalent temperature is 148° F.