Observe structures of the following compounds
The total number of structures/compounds which possess asymmetric carbon atoms is _____.
The total number of structures/compounds which possess asymmetric carbon atoms is _____.
Correct Answer: 3
Solution and Explanation
The correct answer is: 3
Top Questions on Electronic Configurations Of Elements And The Periodic Table
- What is the outer electronic configuration of Gd (Gadolinium, atomic number 64)?
- BCECE - 2025
- Chemistry
- Electronic Configurations Of Elements And The Periodic Table
- Number of valence electrons in Germanium?
- KEAM - 2025
- Chemistry
- Electronic Configurations Of Elements And The Periodic Table
- Which of the following elements does not have a completely filled outermost shell in its ground state?
- MHT CET - 2025
- Chemistry
- Electronic Configurations Of Elements And The Periodic Table
- In which of the following pairs, both the elements do not have \( (n-1)d^{10}ns^2 \) configuration?
- KCET - 2025
- Chemistry
- Electronic Configurations Of Elements And The Periodic Table
- Identify the pair of elements in which the number of electrons in the (n-1) shell is the same:
- AP EAPCET - 2024
- Chemistry
- Electronic Configurations Of Elements And The Periodic Table
Questions Asked in JEE Main exam
The term independent of $ x $ in the expansion of $$ \left( \frac{x + 1}{x^{3/2} + 1 - \sqrt{x}} \cdot \frac{x + 1}{x - \sqrt{x}} \right)^{10} $$ for $ x>1 $ is:
- JEE Main - 2025
- Binomial theorem
- The value of current \( I \) in the electrical circuit as given below, when the potential at \( A \) is equal to the potential at \( B \), will be ________________________ A.
- JEE Main - 2025
- Electrical Circuits
Two cells of emf 1V and 2V and internal resistance 2 \( \Omega \) and 1 \( \Omega \), respectively, are connected in series with an external resistance of 6 \( \Omega \). The total current in the circuit is \( I_1 \). Now the same two cells in parallel configuration are connected to the same external resistance. In this case, the total current drawn is \( I_2 \). The value of \( \left( \frac{I_1}{I_2} \right) \) is \( \frac{x}{3} \). The value of x is 1cm.
- JEE Main - 2025
- Current electricity
If $ \theta \in [-2\pi,\ 2\pi] $, then the number of solutions of $$ 2\sqrt{2} \cos^2\theta + (2 - \sqrt{6}) \cos\theta - \sqrt{3} = 0 $$ is:
- JEE Main - 2025
- Trigonometric Equations
- If \( \int \left( x \sin^{-1} x + \sin^{-1} x (1 - x^2)^{3/2} + \frac{x}{1 - x^2} \right) dx = g(x) + C \), where C is the constant of integration, then \( g\left(\frac{1}{2}\right) \) equals:
- JEE Main - 2025
- Integration by Parts
Concepts Used:
Electronic Configuration of Atoms
Electronic configuration, also called electronic structure, the arrangement of electrons in energy levels around an atomic nucleus. According to the older shell atomic model, electrons occupy several levels from the first shell nearest the nucleus, K, through the seventh shell, Q, farthest from the nucleus. Electrons have to be filled in the s, p, d, f in accordance with the following rule.For example, the electron configuration of sodium is 1s22s22p63s1.
Writing Electron Configurations:
Maximum number of electrons that can be accommodated in a shell is based on the principal quantum number (n). It is represented by the formula 2n2, where ‘n’ is the shell number.
Filling of Atomic Orbitals:
1. Aufbau’s principle: The filling of electrons should take place in accordance with the ascending order of energy of orbitals:
- Lower energy orbital should be filled first and higher energy levels.
- The energy of orbital α(p + l) value it two orbitals have same (n + l) value, E α n
- Ascending order of energy 1s, 2s, 2p, 3s, 3p, 4s, 3d, . . .
2. Pauli’s exclusion principle: No two electrons can have all the four quantum numbers to be the same or if two electrons have to be placed in an energy state they should be placed with opposite spies.
3. Hund’s rule of maximum multiplicity: In the case of filling degenerate (same energy) orbitals, all the degenerate orbitals have to be singly filled first and then only pairing has to happen.